Question

If x+1 is a factor of ax3 + x2 - 2x + 4a-6, find a.
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Answer 1

Step-by-step explanation:

x+1=0

x=-1

f(-1)=a(-1)^3+(-1)^2-2*-1+4a-6

0=a(-1)+1+2+4a+6

0=-a+1+2+4a-6

0=3a-3

3a=3

a=3/3

a=1

Answer 2

Answer:

Given

x+1

Step-by-step explanation:

x+1=0

x=-1

ax3 + x2 - 2x + 4a - 6

a(-1)3 + (-1)2 - 2(-1) + 4a - 6

-3a + 1 +2 + 4a - 6

-3a + 4a -3

a - 3 = 0

a = 3