If x + 1 is a factor of ax3 + x2 – 2x + 4a – 9, find the value of a.
Answers
Answered by
31
Heya !!!
Given that : ( X + 1) is a factor of the given polynomial.
So,
( X + 1) = 0
X = -1
P(X) = AX³+X²-2X+4A-9
P(-1) = A × (-1)³ + (-1)² - 2 × -1 + 4A - 9
=> A × -1 + 1 + 2 + 4A - 9 = 0
=> -A -6 + 4A = 0
=> 3A = 6
=> A = 6/3 = 2
★ HOPE IT WILL HELP YOU ★
Given that : ( X + 1) is a factor of the given polynomial.
So,
( X + 1) = 0
X = -1
P(X) = AX³+X²-2X+4A-9
P(-1) = A × (-1)³ + (-1)² - 2 × -1 + 4A - 9
=> A × -1 + 1 + 2 + 4A - 9 = 0
=> -A -6 + 4A = 0
=> 3A = 6
=> A = 6/3 = 2
★ HOPE IT WILL HELP YOU ★
sabrina789:
ok then answer
but how
Another answer is not deleted
ok
:-(
what should i do now just write in comments
hey
sis plz message me :p
who
saniya
Answered by
12
Hey!!
(x + 1 ) = 0
x = - 1
p (x) = ax^3 + x^2 - 2x + 4a - 9
=> p ( - 1 ) = a( - 1 )^3 + ( - 1 )^2 - 2 ( - 1 ) + 4a - 9
=> 0 = - 1a + 1 + 2 + 4a - 9
=> 0 = 3a + 3 - 9
=> 0 = 3a -6
=> -3a = -6
=> a = 2<<<<<<< Answer
_____________________
Hope it will helps you:-)
(x + 1 ) = 0
x = - 1
p (x) = ax^3 + x^2 - 2x + 4a - 9
=> p ( - 1 ) = a( - 1 )^3 + ( - 1 )^2 - 2 ( - 1 ) + 4a - 9
=> 0 = - 1a + 1 + 2 + 4a - 9
=> 0 = 3a + 3 - 9
=> 0 = 3a -6
=> -3a = -6
=> a = 2<<<<<<< Answer
_____________________
Hope it will helps you:-)
:-)
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