if (x-1) is a factor of ax³+x³-2x+4a-9 then find a
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2
Given ,
x - 1 = 0
x = 1
so,
= ax³+x³-2x+4a-9
= a(1)³+(1)³-2(1)+4a-9
= a + 1 - 2 + 4a -9
= 5a +1-2-9
5a = -10
a= -10/5
a = -2
x - 1 = 0
x = 1
so,
= ax³+x³-2x+4a-9
= a(1)³+(1)³-2(1)+4a-9
= a + 1 - 2 + 4a -9
= 5a +1-2-9
5a = -10
a= -10/5
a = -2
maheshwarahardh:
i think you should have mentioned P(x) so that you can show that the cubic polynomial after substituting with x=1 is 0
ur ans is wrong
sry u r crrct thnx
Answered by
1
I hope that this helps you.
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