Question

If (x-1)is a factor of axcube +bxsquare-36x+22 and 2b= 64a,find a&b

Answer 1

x-1=0
X=1
putting the value of X in the polynomial we get
a+b-36+22=0
a+b-14=0
a+b=14

2b=64a
${2}^{b} = {64}^{a}$
your questions was wrong
the a and b will be the powers of 64 and 2 respectively
${2}^{b} = {2}^{6a}$
removing 2 from both side
b=6a
a+b=14
a+6a=14
7a=14
a=2
a+b=14
2+b=14
b=14-2=12