If (x+1) is a factor of bx^3+x^2-2x+4b-9, find the value of b?
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x+1=0
x=-1
b(-1)^3+(-1)^2-2(-1)+4b-9=0
-b+1+2+4b=9
3b=6
b=2
x=-1
b(-1)^3+(-1)^2-2(-1)+4b-9=0
-b+1+2+4b=9
3b=6
b=2
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