Math, asked by barshushi9936, 11 months ago

If x-1 is a factor of k^2x^3-4kx-1

Answers

Answered by Anonymous
2

Answer:

Step-by-step explanation:

f(x)=k^2x^3-4kx-1

x-1 is a factor of f(x) then

f(1)=0

or k^2*(-1)^3-4k(-1)-1=0

-k^2+4k-1-=0

k^2-4k+1-=0

k=(4±(16-4)^1/2)/2

=(4±√12)/2

=(4±2√3)/2

=2±√3

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