If x-1 is a factor of k^2x^3-4kx-1
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Answer:
Step-by-step explanation:
f(x)=k^2x^3-4kx-1
x-1 is a factor of f(x) then
f(1)=0
or k^2*(-1)^3-4k(-1)-1=0
-k^2+4k-1-=0
k^2-4k+1-=0
k=(4±(16-4)^1/2)/2
=(4±√12)/2
=(4±2√3)/2
=2±√3
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