Question

: If (x-1) is a factor of k(x^2)-√2 x+1 , then value of k is
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Answer 1

Answer:

k= -(√2-1)/2

Step-by-step explanation:

p(x)=kx^2-√2x+1

g(x)=x+2=>x=-2

Thus,

p(x)=p(-2)

=>p(-2)=k(-2)^2-√2(-2)+2

=>4k+2√2+2=0

=>2k+√2+1=0

=>2k=-(√2+1)

=>k= -(√2-1)/2