if X + 1 is a factor of k x cube + x square - 2 X + 4 k - 9 find the value of k
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Answered by
1
Answer:
if x is a factor
x +1 =o, x =-l
thenkx^3+x^2-2x +4k-9=0
-k+I+2+4k-9=0
+3k -6=o
3k=6
k=6/3=2. k=2. Ans
Answered by
6
Answer:
Step-by-step explanation:
Let p(x)=kx³+x²-2x+4k-9
g(x)= x+1
g(x)=0
Therefore, x+1=0, x=-1
Now, putting the value of x i.e. x=-1 in p(x)
p(-1)= k(-1)³+(-1)²-2(-1)+4k-9
=-k+1+2+4k-9
= 3k-6
p(-1)=3k-6=0
Therefore, 3k-6=0
3k=6
k=6/3
So, k =2
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