Math, asked by yashika112360, 1 year ago

if X + 1 is a factor of k x cube + x square - 2 X + 4 k - 9 find the value of k​

Answers

Answered by haridasan85
1

Answer:

if x is a factor

x +1 =o, x =-l

thenkx^3+x^2-2x +4k-9=0

-k+I+2+4k-9=0

+3k -6=o

3k=6

k=6/3=2. k=2. Ans

Answered by asthakumari605
6

Answer:

Step-by-step explanation:

Let p(x)=kx³+x²-2x+4k-9

g(x)= x+1

g(x)=0

Therefore, x+1=0, x=-1

Now, putting the value of x i.e. x=-1 in p(x)

p(-1)= k(-1)³+(-1)²-2(-1)+4k-9

=-k+1+2+4k-9

= 3k-6

p(-1)=3k-6=0

Therefore, 3k-6=0

3k=6

k=6/3

So, k =2

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