Question

If (x – 1) is a factor of k2−√2+1, then find k.

Answer 1

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GIVEN THAT:-

• I Think in your question there is a minor mistake your equation should be as like

$&#10152$ (x – 1) is a factor of k2−√2x+1

SOLUTIONS

$&#10152$ (x – 1) is a factor of k2−√2x+1

so x = 1 is the zero of this equation

$&#10230 \: \: {k}^{2} - \sqrt{2}x + 1 = 0 \: \: \: \: \: \\ \\ &#10230 \: \: {k}^{2} - \sqrt{2} \times 1 + 1 = 0 \\ \\ &#10230 \: \: {k}^{2} = \sqrt{2} - 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ &#10230 \: \: k = \sqrt{ \sqrt{2} - 1 } \: \: \: \: \: \: \: \: \: \:$