If (x-1) is a factor of kx²-√2x+1, then find value of k.
Answers
Answered by
13
Answer:
k=root2-1
Step-by-step explanation:
x-1 is a factor= k(1)^2-root2(1)+1=0 k-root of 2+1=0 k=root over 2-1
Answered by
5
Answer:
k=root 2-1
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