Question

If (x-1) is a factor of kx2 - 2x + 1, then the value of k is, a) v2+1 b)-1+12 c) 2-1 d) v2 -1​

Answer 1

Given -

(x-1) is a factor of kx²-2x+1

To find -

The value of k

Solution -

x-1 is a factor of kx²-2x+1

x-1=0

x=1

p(x)=kx²-2x+1

p(1)=k(1)²-2(1)+1

p(1)=k×1-2+1

p(1)=k-2+1

p(1)=k-1

Since (x-1) is a factor of kx²-2x+1

Therefore remainder is 0

k-1=0

k=1

Therefore the value of k is 1