Question

if (x-1) is a factor of mx²=√2x+1 , then the value of x is



HELPPP (个_个)​

Answer 1

Answer:

x = 1;

m = √2 + 1;

Step-by-step explanation:

if (x-1) is factor of p(x) = 0;

x - 1 = 0

x = 1

Here question must be find value of 'm'

Ans:- for m

=>>

       mx²         =  √2x+1 --(given)

p(x)  = mx² - √2x - 1  =  0        --(eqn. 1)

(x-1) is  factor of mx²=√2x+1 ,

means it satisfy this equation.

x - 1 = 0

x = +1;

put this in p(x)

we know ;

p(x) = 0

p(x)  = mx² - √2x - 1  =  0

p(1)  = m(1)² - √2(1) - 1  =  0

                 m - √2 - 1  =  0

                           m    =  √2 + 1;