Question

If x-1 is a factor of p(x) =2x^2-kx+✓2 then find the value of k
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Answer 1

Step-by-step explanation:

x-1=0

x=1

p(x)=0

2x²-kx+√2=0

2×1²-k×1+√2=0

2-k+√2=0

2+√2=k

k=2+√2

Answer 2

Answer:

if x−1 is a factor of given eqn then it 

will satisfy this eqn ,x−1=0,x=1kx,

2x2+kx+2

2+k+2=0

k=−(2+2) 

Step-by-step explanation:

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