If x – 1 is a factor of p(x)=2x2+kx+2–√p(x)=2x2+kx+2 , k is-
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Answer:
Answer:
x - 1 = 0
x = 1
p(x) =2x^{2}2x
2
+kx +\sqrt{2}
2
p(x) = 2(1)^{2}2(1)
2
+ k(1) + \sqrt{2}
2
= 2 + k + \sqrt{2}
2
2+ k +\sqrt{2}
2
= 0
k = -2 -\sqrt{2}
2
hope it help uh dear!! ✌
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