If (x-1) is a factor of p(x)=3x^4-4x^3-2ax+2a^2,find a
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zero of X.
X=1
p( 3x4 - 4x3 + 2a2 -2ax)
= 3(1)4 - 4(1)3 + 2a2 -2a(1)
=3-4-2a2-2a
0=-1-2a2 -2a
1= -2a ( a + 1)
1/ a+1=-2a
1/a+1*-2=a
1/a-2=a
hence a= 1/a-2
hope it will work thanks. please mark me brainlist.
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