if x+1 is a factor of P(x) = 3x² - kx, then find the value of k
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Step-by-step explanation:
Given :-
x+1 is a factor of P(x) = 3x² - kx
To find :-
Find the value of k ?
Solution :-
Given Quadratic Polynomial P(x) = 3x²-kx
Given factor of P(x) = x+1
We know that
Factor Theorem :-
Let P(x) be a polynomial of the degree greater than or equal to 1 and (x-a) is another linear polynomial if x-a is a factor of P (x) then P(a) = 0 vice-versa.
Given that
(x+1) is a factor of P(x)
=> P(-1) = 0
(Since x+1 = 0 => x = -1)
=> P(-1) = 3(-1)²-k(-1) = 0
=> 3(1)-(-k) = 0
=> 3-(-k) = 0
=> 3+k = 0
=> k = 0-3
=> k = -3
Therefore, k = -3
Answer:-
The value of k for the given problem is -3
Check:-
If k = -3 then
P(x) = 3x²-(-3)x
=> P(x) = 3x²+3x
=> P(x) = 3x(x+1)
=>(x+1) is one of the factors of P(x).
Verified the given relation. in the given problem
Used formulae:-
Factor Theorem :-
- Let P(x) be a polynomial of the degree greater than or equal to 1 and (x-a) is another linear polynomial if x-a is a factor of P (x) then P(a) = 0 vice-versa.
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