Question

if (x-1)is a factor of p(x) =kx square -√2x+1 then find the value of k​

Answer 1

Answer:

k = √2 - 1

Step-by-step explanation:

If (x-1) is a factor of p(x) then, p(1) = 0.

So, k×(1)² - √2×1 + 1 = 0

=> k - √2 + 1 = 0

=> k = √2 - 1

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