if (x-1) is a factor of p(x) =Kx2-√2 x +1 then the value of K is
(a) √2 - 1
(b)- √2 -1
(c) 1 -√2
(d) 1 + √2
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Step-by-step explanation:
Given
x-1 is a factor of kx²-√2x+1
thus
x=1 is one zero of it
now put x= 1
k-√2+1=0
k=√2-1 answers
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