If (X+1) is a factor of
P(X)=x^100-5x^99+6k+3
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x+1=0
x=(-1)
p(-1)=(-1)^100-5(-1)^99+6k+3
0=1-5(-1)+6k+3
0=1+5+6k+3
0=9+6k
6k=(-9)
k=(-9)/6
k=-(3/2)
x=(-1)
p(-1)=(-1)^100-5(-1)^99+6k+3
0=1-5(-1)+6k+3
0=1+5+6k+3
0=9+6k
6k=(-9)
k=(-9)/6
k=-(3/2)
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