Question

if (x+1) is a factor of p(x)=x^3-3x^2+kx what is the value of k

Answer 1

Answer: x+1 = 0

x = -1

p(x) = x³ - 3x² + kx

p(-1) = (-1)³ - 3(-1)² + k(-1) = 0

= -1 - 3(1) - k = 0

= -1 - 3 - k = 0

= -4 = k

The value of k is -4.

Answer 2

Step-by-step explanation:

x + 1 = 0

x + 1 = 0 x + 1 = 0 x = -1

x³ - 3x² + kx = 0

(-1)³ - 3 (-1)² + k-(1) = 0

-1 -3 -k =0

-4 - k =0

k = -4