Physics, asked by amaransh05gmailcom, 10 months ago

If (x+1) is a factor of p( x) = x^98 +2x^37 +p ,find the value p​

Answers

Answered by palaktiwary69
15

X+1=0

X=-1

Explanation:

p(-1)=(-1)^98+2(-1)^37+p

1+2×(-1)+p

1-2+p

-1+p

p(-1)=0

0=-1+p

1=p

hence the value of p is 1

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