Question

if (x-1) is a factor of p (x) =x2 + x+k then the value of k is ____​

Answer 1

Answer:

p(x)=x-1

p(x)=0

or, x-1=0

or, x=1

Let q(x)be x^2+x+k

Using factor theorum

q(1)=1^2+1+k=2+k

q(1)=0

or, 2+k=0

or, k= -2

VALUE OF K IS -2

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Answer 2

Answer:

If (x-1) is a factor of p(x).

then, x-1=0

=> x = 1

p(x) = x2+x+k

p(1)=(1)²+1+k

=> 2+k = 0

=> k = -2

The value of k is -2.