if(x+1) is a factor of polynomial (2x²+kx)then k is
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Answer:
k=2
Step-by-step explanation:
if(x+1) is a factor of polynomial (2x²+kx)then we would find zeroes of (x+1) = x= -1
p(x)=(2x²+kx)
p(-1)=(2*1+k*-1)
now
(2*1+k*-1) =0
2-k=0
-k=-2
k=2
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