If x+1 is a factor of the polynomial 2x square + kx +1 , then the value of 'k' is
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x + 1 is a factor of the polynomial 2x² + kx + 1
then
x + 1 = 0
x = -1
substituting x = -1 in 2x² + kx + 1, it satisfies the polynomial's value to zero
2(-1)² + k(-1) + 1 = 0
2(1) - k + 1 = 0
k = 3
Answered by
2
Answer:
k=3
Step-by-step explanation:
2x² +kx +1 =(x+1)(2x+1)
kx =3x
k=3
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