Question

If (x-1) is a factor of the polynomial
2x² - 2a then find the value of a .​

Answer 1

Answer:

x-1=0

x=1

put x=1

2(1)-2a,0

2-2a=0

2=2a

a=1

Answer 2

Answer:

Given, (x+1) is a factor of p(x) = 2x² - 2a

First we have to find the zero of (x+1) by equating it to zero.

=> x+1 = 0

=> x = 0-1

=> x = -1

As x = -1, we have to substitute this value in p(x).

So,

p(x) = 2(-1)² - 2a

=> p(x) = 2(1) - 2a

=> p(x) = 2 - 2a

As (x+1) is a factor of p(x), p(x) = 0

As p(x) = 2 - 2a,

2 - 2a = 0

=> 2a = - 2

=> a = -2/2

=> a = -1

So, the value of 'a' is -1.