Question

If (x-1) is a factor of the polynomial p(x) = 3x 4 -4x 3 -ax + 2 then find the value of 'a'?

Answer 1

x - 1 = 0

x = 1

If x-1 is factor of given polynomial then if we put the value of x the answer must be equal to zero i.e,

$3 {x}^{4} - 4 {x}^{3} - ax + 2 = 0 \\ \\ 3 {(1)}^{4} - 4 {(x)}^{3} - a(1) + 2 = 0 \\ \\ 3 - 4 - a + 2 = 0 \\ \\ 1 - a = 0 \\ \\ a = 1$

Hope it helps.