If (x-1) is a factor of the second degree polynomial p(x)=ax2+bx+c and p(0)=-5
A) what is the value of c
B) prove that a+b=5
C) write a second degree polynomial whosr one factor is (x-1)
Answers
Answered by
4
Answer:
P(1)=0
⇒x=1
⇒x−1=0
P(−2)=0
⇒x=−2
⇒x+2=0
From (1) and (2), we get,
∴(x−1)(x+2)=0
x
2
+2x−x−2=0
x
2
+x−2=0
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