if X + 1 is a factor of x ^2 - 3a X + 3a - 7 then what is the value of "a?"
Answers
Answered by
92
x+1=0
x= -1
f(x)=0
x²-3ax+3a-7=0
(-1)²-3(a)(-1)+3(a)-7=0
1+3a+3a-7=0
6a-6=0
6a=6
a=6/6
a=1
hope this helps you
x= -1
f(x)=0
x²-3ax+3a-7=0
(-1)²-3(a)(-1)+3(a)-7=0
1+3a+3a-7=0
6a-6=0
6a=6
a=6/6
a=1
hope this helps you
Answered by
25
let given polynomial be f(x)
so f(x) = x^2 -3ax+3a-7
given that ( x+1) is a factor of f(x)
so by using factor theorem
=) x+ 1 = 0
=) x = -1
put x = -1 in f(x)
so f(-1 ) = 0 ---------(1) from factor theorem.
=) (-1)^2 -3a(-1) +3a -7 =0
=) 1 +3a +3a -7 =0
=) 1 + 6a - 7 =0
=) 6a - 6 =0
=) 6a = 6
=) a = 6/6 = 1
=) a = 1 ans.
value of a is 1 ______________________________
hope it will help u
so f(x) = x^2 -3ax+3a-7
given that ( x+1) is a factor of f(x)
so by using factor theorem
=) x+ 1 = 0
=) x = -1
put x = -1 in f(x)
so f(-1 ) = 0 ---------(1) from factor theorem.
=) (-1)^2 -3a(-1) +3a -7 =0
=) 1 +3a +3a -7 =0
=) 1 + 6a - 7 =0
=) 6a - 6 =0
=) 6a = 6
=) a = 6/6 = 1
=) a = 1 ans.
value of a is 1 ______________________________
hope it will help u
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