If X+1 is a factor of x^2-3ax+3a-19 then find the value of a
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the polynomial is x²-3ax+3a-19
The factor is X+1
x+1=0
x=-1
Substitute value of X in given polynomial
(-1)²-3a(-1)+3a-19
1+3a+3a-19
6a-18
As X+1 is a factor
6a-18=0
6a=18
a=18/6
a=3
The factor is X+1
x+1=0
x=-1
Substitute value of X in given polynomial
(-1)²-3a(-1)+3a-19
1+3a+3a-19
6a-18
As X+1 is a factor
6a-18=0
6a=18
a=18/6
a=3
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