if (x+1) is a factor of x^2+px+q and p+q=3, then find the value of p and q
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6
Answer:
(x-1)(x+2)=x^2+x-2
then divide
or
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Answered by
6
Answer:
p+q=3 __________1
p(x) = x² +px+q_____2 , x+1 =0 x= -1
p(-1) = 1² + p(-1) + q
= 1 -p +q
» q = p-1____________3
substituting the value of q in eq 1
p+(p-1) = 3
2p -1 = 3
2p= 3+1
p= 4/2 =2
substituting the value of p in eq 3
q = 2-1
= 1
so the value of p & q are 2 & 1 respectively
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