if X + 1 is a factor of x to the power n + 1 then n is necessarily
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Hey
x + 1 is the factor of xⁿ + 1 , then
n is necessarily an odd number .
Let's take an example :-
a³ + b³ is any number , then it's factor will be ,
( a + b ) ( a² + b² + ab )
But when there will be
a² + b² , then it will not be in factor ,
like as ( a² + b² ) = ( a + b ) ² - 2ab
here in this case , it is not in form of factor .
So, only in case of odd , there will be factor
thanks :)
x + 1 is the factor of xⁿ + 1 , then
n is necessarily an odd number .
Let's take an example :-
a³ + b³ is any number , then it's factor will be ,
( a + b ) ( a² + b² + ab )
But when there will be
a² + b² , then it will not be in factor ,
like as ( a² + b² ) = ( a + b ) ² - 2ab
here in this case , it is not in form of factor .
So, only in case of odd , there will be factor
thanks :)
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