if x + 1 is a factor of X2 - 3 q x + 3q - 7 then value of q is
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Since x+1 is a factor
Therefore By factor theorem ,
x = -1 is zero of the polynomial
Let p(x)= x2- 3qx +3q-7
Substituting x= -1
P(-1)= (-1)2-3q(-1) + 3q-7
0= 1 + 3q+3q -7
0= 6q -6
6=6q
6/6=q
Therefore q=1
Therefore By factor theorem ,
x = -1 is zero of the polynomial
Let p(x)= x2- 3qx +3q-7
Substituting x= -1
P(-1)= (-1)2-3q(-1) + 3q-7
0= 1 + 3q+3q -7
0= 6q -6
6=6q
6/6=q
Therefore q=1
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