if (x+1) is a factor of x³+2x²-5x-6
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Answered by
1
Answer:
Let assume that x+ 1 is a factor
so x= (-1) has to be to zero of the polynomial
putting value of x= (-1) in the polynomial
x³+2x²-5x-6
(-1)^3+2(-1)^2 -5(-1)-6
-1 + 2 +5 -6
7- 6-1
7-7
0
hence it is the factor of the polynomial
Note - it a+ b is the factor of polynomial than a= (-b) is the zero of the polynomial
Answered by
0
Answer:
-10....
Step-by-step explanation:
(X+1)= 0
X=-1
p(X)= x³+2x²-5x-6
p(-1)=(-1)³+2(-1)²-5(-1)-6
= -1+2-5-6
= -7-3
= -10
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