If (x-1) is a factor of x³+7x²+ax-3, find the value of a.
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Step-by-step explanation:
Let p ( x ) = x³ + 7x² + ax - 3 = 0
If ( x - 1 ) is a factor of p ( x ) ,then x - 1 = 0 ⇒ x = 1.
On substituting,
p ( 1 ) = ( 1 )³ + 7 ( 1 )² + a ( 1 ) - 3 = 0
⇒ 1 + 7 ( 1 ) + a - 3 = 0
⇒ 1 + 7 + a - 3 = 0
⇒8- 3 + a = 0
⇒ 5 + a = 0
⇒ a = - 5 is the answer.
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If (x-1) is a factor of x³+7x²+ax-3, find the value of a.
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