Question

if (x-1) is a factor of (x³-kx²+11x-6) find the value of k?
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Answer 1

Step-by-step explanation:

x-1=0

so, x=1.........( a)

putting the value of (a) in eq.

x^3- kx^2+11x-6

= (1)^3- k(1)^2+11×(1)-6

= 1-k+11-6

= 1-k+5

=k-6

0 = k-6

k = 6

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Answer 2

Step-by-step explanation:

$\bf \underline{Solution-}$

∵ (x - 1) is a factor of p(x)

∴ By factor theorem, we are p(1) = 0

⇒ (1)³ - k(1)² + 11(1) - 6 = 0

⇒1 - k + 11 - 6 = 0

⇒ 6 - k = 0

⇒k = 6

Hence, the value of k is 6.