If (x+1) is a factor of x³+mx²+19x+12.find the value of m
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p(x) = x³+mx²+19x+12
x+1 is the factor so
x+1=0
x= -1
now putting the value of x in above p(x)
we get,
x³+mx²+19x+12 = 0
=>( -1)³+m(-1)²+19(-1)+12= 0
= -1+m-19+12 = 0
= m-20+12= 0
= m-8 = 0
=> m= 8
hope this helps you
x+1 is the factor so
x+1=0
x= -1
now putting the value of x in above p(x)
we get,
x³+mx²+19x+12 = 0
=>( -1)³+m(-1)²+19(-1)+12= 0
= -1+m-19+12 = 0
= m-20+12= 0
= m-8 = 0
=> m= 8
hope this helps you
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