Question

If (x – 1) is a factor of x4 - 3x3 + bx2 + 8x – 4, then find the value of b.​

Answer 1

Answer:

x-1=0

x=1

if x is a factor of this equation

so we can

x^4 -3x^3 +bx^2 +8x -4

put x = 1

(1)^4 -3(1)^3 +b(1)^2 +8(1) -4

1 -3+b +8 -4

b=2