Question

If x+1 is a factor of x4 +(p-3)x3-(3p-5) of x2+(2p-9)x+6.what is the value of p
.

Answer 1

Answer:

If (x−1) and (x−2) are factors of x4−(p−3)x3−(3p−5)x2+(2p−9)x+6 then the value of p is:

A .

1

B .

2

C .

3

D .

ANSWER

The zero of any one of the factors will satisfy the equation:

x4−(p−3)x3−(3p−5)x2+(2p−9)x+6=0

Select (x−1)=0, which implies x=1

Using this in f(x)=x4−(p−3)x3−(3p−5)x2+(2p−9)x+6=0

we get f(1)=14−(p−3)13−(3p−5)12+(2p−9)1+6=0

which implies, p=3

Answer 2

Step-by-step explanation:

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