Question

if (x-1) is a factor of x5-3x4-ax3+3ax2+2ax+4 then the value of a is
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Answer 1

Answer:

x-1= 0

x= 1

p(x)= x^5-3x^4-ax^3+3x^2+2ax+4

p(1)= 1-3-a+3a+2a+4

= -2-a+3a+2a+4

= 2+4a

2+4a=0

= 4a= -2=

a= -2/4=

a= -1/2

Hope it helps