Question

if (x+1)is a factor of xsquare -kx+3k - 7,then the value of k is ________​

Answer 1

Given :

• $\tt\small{(x+1)\: is\: a \:factor\: of \:x² \:-\: kx \:+ \:3k}$$\tt\small{ - \:7}$

To Find :

• $\tt\small{Value \:of \:k \:= \:?}$

Solution :

$\tt\small{As, \:(x+1)\: is\: a \:factor \:of \:x²\: -\: kx \:+\:3k\:-\:7}$$\tt\small{7.}$

x + 1 = 0

x = - 1

Hence, x = - 1 is root of x² - kx + 3k - 7.

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Therefore, We can write

p(x) = x² - kx + 3k - 7 as :

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p(-1) = (-1)² - k(-1) + 3k - 7 = 0

$\sf : \implies 1 + k + 3k - 7 = 0$

$\sf : \implies 4k - 6 = 0$

$\sf : \implies 4k = 6$

$\sf : \implies k = \dfrac{\cancel{6}^{3}}{\cancel{4}_{2}}$

$\sf : \implies k = \dfrac{3}{2}$

Therefore, value of k = $\sf \dfrac{3}{2}$

Answer 2

Answer:

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