If x-1 is a factor to p(x) hx = ^{2}hx
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p(x) = (x – a)q(x) + r(x) If x – a is indeed a factor of p(x), then the remainder after division by x – a will be zero. That is: p(x) = (x – a)q(x) In terms of the Remainder Theorem, this means that, if x – a is a factor of p(x), then the remainder, when we do synthetic division by.
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