if (x+1) is a zero of px cube +2x square +5x+4 then find p
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4
Answer:
p=1
Step-by-step explanation:
g(x)=x+1
x+1=0
x=(-1)
p(x)=px³+2x²+5x+4=0
p(-1)=p(-1)³+2(-1)²+5(-1)+4=0
-p+2-5+4=0
p=4-3
p=1
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