Math, asked by rakahi0404, 1 year ago

if x=1 is a zero of the polynomial f(x)=x^3-2x^2+4x+k,find the value of 'k'

Anonymous: hiii

Answers

Answered by joshiveerendrakumar

Answer:

Step-by-step explanation:

1-2+4+k=0

K=-5

rakahi0404: I am sorry to say its +3

Answered by antareepray2

As 1 is a zero of f(x), then f(1) should be equal to 0. Hence, the reqd. equation

$= > f(1) = {1}^{3} - 2( {1}^{2} ) + 4(1) + k = 0 \\ = > 1 - 2 + 4 + k = 0 \\ = > k = ( - 3)$

HOPE THIS COULD HELP!!!

rakahi0404: I am sorry to say its +3

antareepray2: I am sorry....but I have checked....it's (-3)....please kindly review the question....

rakahi0404: +1+4=+5 +5-2=+3 right

rakahi0404: ??

rakahi0404: please clarify it

antareepray2: 1-2+4+k = 0 or, 1+4-2 +k = 0 or, 5-2+k = 0 or, 3 + k = 0 or, k = -3

antareepray2: The 3 becomes -3 when it move to the R.H.S. of '='

antareepray2: Your calculation is correct but you haven't changed the sign....

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