if x=1 is a zero of the polynomial f(x)=x^3-2x^2+4x+k,then the value of 'k'is
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Polynomial :- x³ – 2x² + 4x + k = 0.
Zero Of Polynomial :- x = 1.
Solution :-
If x = 1, then put its value in the given expression.
⇒ (1)³ – 2(1)² + 4(1) + k = 0.
⇒ 1 – 2 + 4 + k = 0.
⇒ –1 + 4 + k = 0
⇒ –3 = k.
Hence, The Value Of k = –3.
Verification :-
⇒ (1)³ – 2(1)² + 4(1) + (–3) =0.
⇒ 1 – 2 + 4 + (–3) = 0.
⇒ 3 – 3 = 0.
⇒ 0 = 0.
LHS = RHS.
Hence, Verified.
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