Question

If x=1 is a zero of the polynomial f (x)=x2-5x+k, then the value of k is:
यदि 1=1 बहुपद f (3)=1-51 +K का शून्यक है, तो ५ मान है :
(A) -- 6
| (B) -4
(C) 4
(D) 6​

Answer 1

Answer:

$f(x) = {x}^{2} - 5x + k$

$f(1) = {1}^{2} - 5(1) + k$

$f(1) = k - 4$

$k - 4 = 0$

$k = 4$

$option \: (c) \: 4$

Hope it helps..

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Answer 2

Answer:The answer is (C) 4 according to me...

Step-by-step explanation: