if x=1 is a zero of the polynomial f (x)=x2â’5x+k, then the value of k is
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if X=1 is a zero of f(x)=x²+5x+k,
then
f(1)=0
hence
(1)² +5×1 +k=0,
1+5+k=0,
then
k=-6
then
f(1)=0
hence
(1)² +5×1 +k=0,
1+5+k=0,
then
k=-6
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