Question

If x = 1 is a zero of the polynomial p(x) = x4 – 5x3 – 20x2 + 130x – a, then the value of a is

Answer 1

Step-by-step explanation:

$\huge\purple{\tt{\underbrace{\overbrace{\ulcorner{\mid{\overline{\underline{Answer:}}}}}}}}$

x=1

p(1)=(1)*4-5(1)³-20(1)²+130(1)-a

=1-5-20+130-a

-4-20+130-a

-4+110-a

105=a

a=105 is the answer

Answer 2

${ \red{ \underline{ \underline{ \huge{ \mathfrak{Given}}}}}}$

$p(x) = x {}^{4} - 5x {}^{3} - 20 {}^{2} + 130x - a$

$x = 1$

${ \blue{ \underline{ \underline{ \huge{ \mathfrak{we \: have \: to \: find \: the \: value \: of \: a}}}}}}$

a=?

${ \green{ \underline{ \underline{ \huge{ \mathfrak{Solution}}}}}}$

$p(x) = x {}^{4} - 5x {}^{3} - 20x {}^{2} + 130x- a = 0\\ p(1) = (1) {}^{4} - 5(1){}^{3} - 20(1){}^{2} + 130(1) - a = 0 \\ \: \: = 1 - 5 - 20 + 130 - a = 0 \\ = 131 - 25 - a = 0 \\ 106 - a = 0 \\ a = 106$

${ \pink{ \underline{ \underline{ \huge{ \mathfrak{mark \: it \: brainliest \: answer }}}}}}$

${ \pink{ \underline{ \underline{ \huge{ \mathfrak{have \: a \: nice \: day}}}}}}$