Question

If x = 1 is common root of the equations ax² + ax + 3 = 0 and x2 + x + b =0 then value of ab is​

Answer 1

Answer:

3

Step-by-step explanation:

Putting x = 1 in equation

ax2 + ax + 3 = 0

⇒ a(1)2 + a(1) + 3 = 0

⇒ a + a + 3 = 0

⇒ 2a = – 3

⇒ a = -3/2

AND

putting x = 1 in equation

x2 + x + b = 0

⇒ (1)2 + (1) + b = 0

⇒ 1 + 1 + b = 0

⇒ b = -2

So,

ab = -3/2 × -2 = 3