If x - 1 is factor of 2x-11x² + bx - 6 then b =
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GIVEN FUNCTION :–
2 X³ - 11 X² + bx - 6 =0
TO FIND :–
VALUE OF "b"
SOLUTION :–
=》 2 x³ - 11 x² + b x - 6 = 0 , it's one factor is (x - 2) .
● SO , THAT PUT X = 2 in EQUATION –
=》 2 (2)³ - 11(2)² + 2b - 6 = 0
=》 16 - 11 × 4 + 2b - 6 = 0
=》 16 - 44 - 6 + 2b = 0
=》 2b - 34 = 0
=》 b = 17
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Answered by
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Answer:
15
Step-by-step explanation:
If x-1 is factor of p(x)=2x-11x^2+bx-6 then by factor theorm p(1)=0
2(1)-11(1^2)+b(1)-6=0
2-11+b-6=0
b-15=0
b=15
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