If x+1 is factor of 2x3+ax2+2bx+1, then find the value of a and b given that 2a-3b=4
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If x + 1 is factor then x = - 1
Factor theorum states that p( x ) = 0
Here,
p( x ) = 2x^3 + ax^2 + 2bx + 1
p( - 1 ) = 2(-1)^3 + a(-1)^2 + 2b(-1) + 1
0 = - 2 + a - 2b + 1
0 = - 1 + a - 2b
a - 2b = 1 ------(1)
Now its given that = > 2a - 3b = 4 -----(2)
If we multiply - 2 from (1)
We get , - 2a + 4b = - 2 ------(3)
Add (2) and (3)
We get, b = 2
Then a => a - 2( 2 ) = 1
a - 4 = 1
a = 5
Hope it helps☺!✌
If x + 1 is factor then x = - 1
Factor theorum states that p( x ) = 0
Here,
p( x ) = 2x^3 + ax^2 + 2bx + 1
p( - 1 ) = 2(-1)^3 + a(-1)^2 + 2b(-1) + 1
0 = - 2 + a - 2b + 1
0 = - 1 + a - 2b
a - 2b = 1 ------(1)
Now its given that = > 2a - 3b = 4 -----(2)
If we multiply - 2 from (1)
We get , - 2a + 4b = - 2 ------(3)
Add (2) and (3)
We get, b = 2
Then a => a - 2( 2 ) = 1
a - 4 = 1
a = 5
Hope it helps☺!✌
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